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The nessler's reagent is

Option: 1

K2HgI4


Option: 2

HgI2


Option: 3

NH2-Hg-O-Hg-I


Option: 4

K2HgI4 + KOH


Answers (1)

best_answer

As we learnt ,

 

Ammonia and its salt with nessler's reagent -

Gives brown precipitate due to the formation of Millon's base

- wherein

  1. K_{2}HgI_{4}\rightleftharpoons 2KI+HgI_{2}
  2. HgI_{2}+2NH_{3}\rightarrow I-Hg-NH_{2}+NH_{4}I
  3. 2NH_{2}-Hg-I+H_{2}O\rightarrow NH_{2}-Hg-O-Hg-I+NH_{4}I
  4. 2K_{2}HgI_{4}+NH_{3}+3KOH\rightarrow H_{2}N-Hg-O-Hg-I+7KI+2H_{2}O

 

 Nessler's reagent is the mixture of K2HgI4  and KOH.

Therefore, option (4) is correct.

 

Posted by

Shailly goel

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