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The number of ways in which two teams \mathrm{A} and \mathrm{B} of 11 players each can be made up from 22 players so that two particular players are on the opposite sides is

Option: 1

369512


Option: 2

184755


Option: 3

184756


Option: 4

369514

 


Answers (1)

best_answer

We can choose 10 players from (22-2) players in \mathrm{{ }^{20} C_{10}} ways and one player from 2 players in \mathrm{{ }^{2} C_{1}} ways.

\therefore   required number of ways

=\frac{20 !}{10 ! 10 !} \times 2=369512

Posted by

vishal kumar

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