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The number of ways in which two teams can be formed out of 7 students so that one has 3 members and other has 4 members 

Option: 1

35 


Option: 2

40 


Option: 3

45 


Option: 4

50 


Answers (1)

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As we have learned

Rule for Division into Groups -

The number of ways in which (m + n) different things can be divided into two groups which contain m and n things respectively is \frac{(m+n)!}{m!\ n!}.

 

Now,

Number of ways = \frac{7 !}{3!4!} = \frac{7\times 6 \times 5 }{6}= 35

 

Posted by

manish painkra

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