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  • The osmotic pressure exerted by a solution prepared by dissolving  of protein

The osmotic pressure exerted by a solution prepared by dissolving 2.0 \mathrm{~g} of protein of molar mass 60 \mathrm{~kg} \mathrm{~mol}^{-1} in 200 \mathrm{~mL} of water at 27^{\circ} \mathrm{C} is __________Pa.[integer value]

\text { (use } \mathrm{R}=0.083 \mathrm{~L} \text { bar } \mathrm{mol}^{-1} \mathrm{~K}^{-1} \text { ) }

Option: 1

415


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\begin{aligned} \\&\text{n}=\frac{2}{60 \times 10^{3}}=3.33 \times 10^{-5} \\ \\&\therefore[\operatorname{Protein}]=\text{C}=1.67 \times 10^{-5} \\ \\&\therefore \mathrm{\pi=C R T}=1.67 \times 10^{-5} \times 0.083 \times 300 \end{aligned}

                             \begin{aligned} &=4.15 \times 10^{-3} \text { bar } \\ &=415 \mathrm{~Pa}\left(\because 1\; \mathrm{bar}=10^{5}\text{Pa}\right) \end{aligned}

Hence, the answer is 415.

Posted by

shivangi.shekhar

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