Get Answers to all your Questions

header-bg qa

The pH of a 0.1 molar solution of the acid HQ is 3. The value of the ionization constant, Ka of this acid is :

Option: 1

3\times 10^{-1}


Option: 2

1\times 10^{-3}


Option: 3

1\times 10^{-5}


Option: 4

1\times 10^{-7}


Answers (1)

Given,

pH=3

Molarity = 0.1 M

\left [ H^{+} \right ]=\sqrt{K_{a}C}

H^{+}=10^{-pH}=10^{-3}

10^{-3}=\sqrt{K_{a}\times 0.1}\;\;\; or\; \; 10^{-6}=K_{a}\times 0.1

\therefore \; \; K_{a}=10^{-5}    

Therefore, the option number (3) is correct.

Posted by

Kshitij

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions