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  • The pressure of a gas inside a tyre is 4atm at 300K. If the tyre bursts suddenly,it's final temperature will be?

The pressure of a gas inside a tyre is 4atm at 300K. If the tyre bursts suddenly,it's final temperature will be?

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\\\text{Under adiabatic change }\\ \frac{T_{2}}{T_{1}}=\left(\frac{P_{1}}{P_{2}}\right)^{\frac{1-\gamma}{\gamma}}$ \\ or $T_{2}=T_{1}\left(\frac{P_{1}}{P_{2}}\right)^{\left(\frac{1-\gamma}{\gamma}\right)}$ \\\\ $\therefore T_{2}=300(4)^{\frac{1-j / 5}{7 !}} ; \gamma=1.4=7 / 5$ for air \\\\ or $T_{2}=300(4)^{-2 / 7}$

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