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The rate constant for a reaction of zero Order in A is 0.0060 \mathrm{molL { }^{-1} s^{-1}}. How long will it take for the initial concentration of A to fall from 1.40 \mathrm{M} to \mathrm{0.27 \mathrm{M}} ?

Option: 1

150 \mathrm{sec}\, \,


Option: 2

249\, \mathrm{sec}


Option: 3

322\, \mathrm{sec}


Option: 4

188\, \, \mathrm{sec}


Answers (1)

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\mathrm{\begin{aligned} & t=\frac{1}{k}\left[\left(A_0\right)-(A)\right] \\ & t=\frac{1}{0.006}[(1.40-0.27)] \\ & t=\frac{1}{0.006} \times 1.13 \\ & t=188.3 \mathrm{sec} \\ & t \approx 188 \end{aligned} }

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