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The rate law for the reaction,  \mathrm{RCl + NaOH(aq) \rightarrow ROH + NaCl}  is given by Rate = k[RCl]. The rate of reaction will be –

Option: 1

Doubled on doubling the concentration of NaOH


Option: 2

Halved on reducing the concentration of alkyl halide to one-half


Option: 3

Decreases on increasing the temperature


Option: 4

Unaffected by increasing the temperature


Answers (1)

best_answer

As given, the rate of reaction = k[RCl]

So, it clearly does not depend upon the concentration of NaOH. 

Rate shall halve on halving the concentration of alkyl halide. 

Further, the increase in temperature increases the rate of reaction. 

 

Posted by

HARSH KANKARIA

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