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The ratio of amounts of H2S needed to precipitate all the metals ions from 100 ml of 1 M AgNO3 and 100 ml of 1 M CuSO4 is:

 

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\begin{aligned} &2 \mathrm{AgNO}_{3}+\mathrm{H}_{2} \mathrm{S} \rightarrow \mathrm{Ag}_{2} \mathrm{S}+2 \mathrm{HNO}_{3}\\ &\mathrm{CuSO}_{4}+\mathrm{H}_{2} \mathrm{S} \rightarrow \mathrm{CuS}+\mathrm{H}_{2} \mathrm{SO}_{4}\\\\ &\text {2mol AgNO}_{3} \text{ requires } 1 \text { mol } \mathrm{H}_{2} \mathrm{S} \end{aligned}

\begin{aligned} &\therefore 1 \mathrm{mol} \quad \text { AgN} \mathrm{O}_{3} \quad \text { requires } \quad 1 / 2 \quad \mathrm{mol} \quad \mathrm{H}_{2} \mathrm{S}\\ &\text { 1 mol } \mathrm{CuSO}_{4} \text { requires } 1 \mathrm{mol} \quad \mathrm{H}_{2} \mathrm{S}\\ &\therefore \text { ratio of } \mathrm{H}_{2} \mathrm{S} \text { requires to precipitate } \mathrm{AgNO}_{3} \text { to } \mathrm{CuSO}_{4} \text { will be } 1 / 2: \text { or1 : } 2 \end{aligned}

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