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  • The ratio of weight of mass m a stationary lift and a lift accelerated downwards with uniform acceleration 'a' is 3 : 2 . The acceleration of lift is <stron

The ratio of weight of mass m a stationary lift and a lift accelerated downwards with uniform acceleration 'a' is 3 : 2 . The acceleration of lift is 

Option: 1

g/3 


Option: 2

g/2 


Option: 3

g 


Option: 4

2g


Answers (1)

best_answer

As we have learned

Lift is at Rest -

V=0,\:a=0

R-mg=0

R=mg

- wherein

use

F_{net}=m\vec{a}
 

Apparent \:weight=Actual\:weight
 

 

 

 At stationary lift 

R_1 = mg

At lift accelerated downwards with a 

mg - R = ma \\ R_2 = mg -ma \Rightarrow m (g-a )

Given \frac{R_1}{R_2}= \frac{3}{2} = \frac{mg}{m(g-a)}

\frac{g}{(g-a)} =\frac{3}{2}\Rightarrow 2 g = 3g -3a \\

or 

a = g/3 

 

Posted by

Divya Prakash Singh

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