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  • The rms value of an ac of 50 Hz is 10 A. The time taken by an alternating current in reaching from zero to maximum value and the peak value of current will be:Op

The rms value of an ac of 50 Hz is 10 A. The time taken by an alternating current in reaching from zero to maximum value and the peak value of current will be:

Option: 1

2 \times 10^{-2} \mathrm{~s} \text { and } 14.14 \mathrm{~A}


Option: 2

1 \times 10^{-2} \mathrm{~s} \text { and } 7.07 \mathrm{~A}


Option: 3

5 \times 10^{-3} \mathrm{~s} \text { and } 7.07 \mathrm{~A}


Option: 4

5 \times 10^{-3} \mathrm{~s} \text { and } 14.14 \mathrm{~A}


Answers (1)

Here,\mathrm{ I_v=10 A, v=50 \mathrm{~Hz} }

\mathrm{\mathrm{I}_0=\sqrt{2} \mathrm{I}_{\mathrm{v}}=1.414 \times 10=14.14 \mathrm{~A} }

Time taken to reach from zero to maximum value
\mathrm{\mathrm{t}=\frac{\mathrm{T}}{4}=\frac{1}{4 \mathrm{v}}=\frac{1}{4 \times 50} \mathrm{~s}=\frac{1}{200} \mathrm{~s}=5 \times 10^{-3} \mathrm{~s} }
 

Posted by

Ramraj Saini

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