Get Answers to all your Questions

header-bg qa

The self inductance of the motor of an electric fann is 10 Henry.In order to impart maximum power at 50 Hz it should be connected to a capacitance of

Option: 1

\mathrm{3 \times 10^{-6} Farad}


Option: 2

\mathrm{2 \times 10^{-5} Farad}


Option: 3

\mathrm{10^{-4} Farad}


Option: 4

\mathrm{10^{-4} Farad}


Answers (1)

best_answer

For naximum power to be transferred

\mathrm{\begin{aligned} &X_L=X_c \text { or } L_\theta=\frac{1}{C_\theta}\\ &\text { or } \mathrm{C}=\frac{1}{\mathrm{~L} \omega^2}=\frac{1}{10 \times(100 \pi)^2}=10^{-4} \mathrm{~F} \end{aligned}}

Posted by

Rishi

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE