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  • The standard hydrolysis constant of anilinium acetate: Ka(CH3COOH) = 1.8  10

The standard hydrolysis constant of anilinium acetate:
Ka(CH3COOH) = 1.8 \times 10-5 M, Kb(aniline) = 4.6 \times 10-10 M at 25o C is:

Option: 1

5.6


Option: 2

1.45


Option: 3

1.21


Option: 4

1


Answers (1)

best_answer

We know this formula,

\\K_{h}=\frac{K_{w}}{K_{a} K_{b}} \\K_{h} =\frac{1.0 \times 10^{-14}}{\left(1.8 \times 10^{-5} \mathrm{M}\right)\left(4.6 \times 10^{-10} \mathrm{M}\right)} \\ \\K_{h} =1.21

Therefore, option(3) is correct

Posted by

vinayak

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