Numbers that are divisible by 2 and 5 are 2,4,5,6,8,10.............92,94,95,96,98,100.
A1 = 2,4,6,8,10,...100 are in AP with common difference(d1) = 2. & A2 = 5,10,15,...100 are also in AP with common difference (d2 =5).
and A3 = 10,20,30......100 are also in AP with common diff. (d3) = 10.
n term of A1 A2 & A3 can be obtain by using formula, [a + (n-1)d = last term] ,
so total no. of terms in A1 , A2 & A3 are 50, 20, 10 resp.
S1 = N1/2{2a +49d1} , S2 = N2/2{2a +19d2} & S3 = N3/2{2a + 9d3}
S1 = 50/2{2*2 + 49*2} = 25{4+98} =2550
S2 = 20/2{2*5 + 19*5} = 10{10+95} =1050
S3 = 10/2{2*10 + 9*10} = 5{20+90} = 550
total sum = S1+ S2 -S3 = 3050
correct : Option (B)
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