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The terminal velocity \left(v_{\mathrm{t}}\right) of the spherical rain drop depends on the radius ( r ) of the spherical rain drop as :
 

Option: 1

\mathrm{r}^{1 / 2}


Option: 2

\mathrm{r}


Option: 3

\mathrm{r}^{2}


Option: 4

r^{3}


Answers (1)

best_answer

For the spherical raindrops, the terminal velocity is equal to

\mathrm{V_{t}= \frac{2r^{2}\left ( \rho_{drop}-\rho_{air} \right )g}{9\eta }}
\mathrm{V_{t} \propto r^2}

The correct option is (3)

Posted by

Sayak

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