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  • The vapour pressure of a solution of a non-volatile non electrolyte (A) in a solvent (B) is 95% of the vapour pressure of the solvent at the same temperature. If MB = 0.3 MA</s

The vapour pressure of a solution of a non-volatile non electrolyte (A) in a solvent (B) is 95% of the vapour pressure of the solvent at the same temperature. If MB = 0.3 MA, where MB and MA are molar masses of B and A respectively, the mass ratio of the solvent and solute are:

Option: 1

5.7


Option: 2

0.2


Option: 3

0.15


Option: 4

4


Answers (1)

best_answer

As we know:

\frac{\mathrm {P^{0}-P}_{\mathrm{s}}}{\mathrm P_{\mathrm{s}}}=\frac{\mathrm n}{\mathrm N}=\frac {\mathrm{w \times M}} {\mathrm{m \times W}}

\frac{\mathrm P^{0}-\frac{95}{100} \mathrm P^{0}}{\frac{95}{100} \mathrm P^{0}}=\frac{\mathrm w \times 0.3 \mathrm{m}}{ \mathrm W \times \mathrm m}\: \: \: \: \: (M=0.3 \mathrm{m})

\frac{\mathrm W}{\mathrm w}=5.7

 

Posted by

Ritika Harsh

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