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  • The velocity-displacement graph of a particle is shown in the figure. Option: 1 <img alt="" src="https://cdn.entr

The velocity-displacement graph of a particle is shown in the figure.
Option: 1
Option: 2
Option: 3
Option: 4

Answers (1)

best_answer


Equation from this graph using straight line equation - 
v =-\left(\frac{ v _{0}}{ x _{0}}\right) x + v _{0}
\begin{array}{l} a =\frac{ vdv }{ dx } \\ \\ a =\left[-\left(\frac{ v _{0}}{ x _{0}}\right) x + v _{0}\right]\left[-\frac{ v _{0}}{ x _{0}}\right] \\ \\ a =\left(\frac{ v _{0}}{ x _{0}}\right)^{2} x -\frac{ v _{0}^{2}}{ x _{0}} \end{array}

Since the intercept is negative and slope is positive. So the correct option is (3)

Posted by

Deependra Verma

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