Get Answers to all your Questions

header-bg qa

The volume of gas A is twice than that of gas B. The compressible-ility factors of gas A is thrice than that of gas B at same temperature. The pressure of the gases for equal number of moles are -
 

Option: 1

\mathrm{P_A=2 P_B }


Option: 2

\mathrm{2 P_A=3 P_B }


Option: 3

\mathrm{3 P_A=2 P_B }


Option: 4

None of these


Answers (1)

best_answer

given, \mathrm{ z_A=3 z_B}
\mathrm{ \text { compressibility factor }(z)=\frac{P V}{n R T} \text { (forroud gases) } }
On substituting in equation we get.

\mathrm{ \frac{P_A V_A}{n_A R T_A}=\frac{3 P_A V_B}{n_B R T_B} }

Also, it is given that,

\mathrm{v_A=2 v_B, n_A=n_B \text { and } T_A=T_B}

Equation (1) becomes,

\begin{aligned} & \mathrm{\frac{P_A \times 2 V_B}{n_B R T_B}=\frac{3 P_B V_B}{n_B R T_B} }\\ &\mathrm{ \Rightarrow 2 P_A=3 P_B} \end{aligned}
 

Posted by

Ritika Kankaria

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE