Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • The wavelength of the first line of Lyman series for hydrogen atom is equal to that of the second line of Balmer series for a hydrogen like ion. The atomic number Z of hydrogen like ion is:<div

The wavelength of the first line of Lyman series for hydrogen atom is equal to that of the second line of Balmer series for a hydrogen like ion. The atomic number Z of hydrogen like ion is:

Option: 1

4


Option: 2

1


Option: 3

2


Option: 4

3


Answers (1)

best_answer

Lyman series of H-atom, we can write \frac{\mathrm{hc}}{\lambda}=\operatorname{Rhc}\left(\frac{1}{1^2}-\frac{1}{2^2}\right)

Where, symbols have their usual meaning and for second line of Balmer series of H-like ion

\frac{\mathrm{hc}}{\lambda}=\mathrm{Z}^2 \operatorname{Rhc}\left(\frac{1}{2^2}-\frac{1}{4^2}\right)

\text { Therefore, }\left(\frac{1}{1^2}-\frac{1}{2^2}\right)=Z^2\left(\frac{1}{4}-\frac{1}{16}\right)

\left(1-\frac{1}{4}\right)=Z^2\left(\frac{1}{4}-\frac{1}{16}\right) \Rightarrow Z=2.19=2

 

 

Posted by

vinayak

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2026 session 2 application correction begins on jeemain.nta.nic.in; edit details by tomorrow
anam-khan

JEE Main 2026 Registration LIVE: Session 2 exam from April 2 to 9; shift timings, admit card, exam pattern
anam-khan

JEE Main 2026 session 2 registration ends today for BTech, BArch; apply at jeemain.nta.nic.in

Latest Question