Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Three block m1= 1kg , m2 = 1.5kg and m3 = 2kg are in contact with each other on frictionless surface as shown in figure. What will be the contact for

Three block m1= 1kg , m2 = 1.5kg and m3 = 2kg are in contact with each other on frictionless surface as shown in figure. What will be the contact force between m2 and m3 if the value of F is 18N?

 

Option: 1

10N


Option: 2

8N


Option: 3

6N


Option: 4

12N


Answers (1)

best_answer

Solution :

\\ \text{Given :} \\m_{1}=1kg \\ m_{2}=1.5kg \\ m_{3}=2kg \\ F=18N

\\ \text{Let common acceleration of all the blocks be 'a' }

\\ \text{F.B.D of all the blocks combined}

\\ \text{From newton's 2nd law-}

\\ a=\frac{F}{m_{1}+m_{2}+m_{3}}

\Rightarrow a=\frac{18}{1+1.5+2}=4m/s^2\\ \text{Let normal reaction betweeen the blocks of mass 1.5kg and 2 kg be 'N'. }

N=m_{3}a=2\times4

\therefore N=8N

Posted by

manish

View full answer

Similar Questions

Trending Articles/News

anam-khan

AP EAMCET second phase results 2025 for agriculture, pharmacy on June 25
anam-khan

AP EAMCET Counselling 2025: Cut-offs for agricultural engineering, BTech ECE closing ranks
anam-khan

AP EAMCET cut-offs 2025 for BTech civil, chemical engineering in top colleges; counselling soon

Latest Question