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  • Three numbers are chosen at random without replacement from {1, 2, 3, ...... 8}. The probability that their minimum

Three numbers are chosen at random without replacement from {1, 2, 3, ...... 8}. The probability that their minimum is 3, given that their maximum is 6, is

Option: 1

\frac{3}{8}


Option: 2

\frac{1}{5}


Option: 3

\frac{1}{4}


Option: 4

\frac{2}{5}


Answers (1)

best_answer

As learnt

Conditional Probability -

 

P\left ( \frac{A}{B} \right )= \frac{P\left ( A\cap B \right )}{P\left ( B \right )}

and

P\left ( \frac{B}{A} \right )= \frac{P\left ( A\cap B \right )}{P\left ( A \right )}

 

- wherein

where the probability of A when B already happened.

A is the event that the maximum  is 6.

B is the event that the minimum is 3.

Posted by

Shailly goel

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