Train A and B are running on a parallel tracks in the opposite direction with speeds of 36 Km/hour and 72 Km/hour respectively. A person is walking in train A in the direction opposite to its motion with a speed of 1.8 km/hour. Speed (in ms-1) of this person as observed from train B will close to :(take the distance between the tracks as negligible)
Option: 1 29.5
Option: 2 28.5
Option: 3 31.5 
Option: 4 30.5 

Answers (1)

  The velocity of a man with respect to ground
\overrightarrow{\mathrm{V}}_{\mathrm{m} / \mathrm{g}}=\overrightarrow{\mathrm{V}}_{\mathrm{m} / \mathrm{A}}+\overrightarrow{\mathrm{V}}_{\mathrm{A}}=-1.8+36
The velocity of man w.r.t. B

\overrightarrow{\mathrm{V}}_{\mathrm{m} / \mathrm{B}}=\overrightarrow{\mathrm{V}}_{\mathrm{m}}-\overrightarrow{\mathrm{V}}_{\mathrm{p}} =-1.8+36-(-72) =106.2 \mathrm{~km} / \mathrm{hr} =29.5 \mathrm{~m} / \mathrm{s}

 

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