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  • Try this! 2- methylbutane on reacting with bromine in the presence of sunlight gives mainly

2- methylbutane on reacting with bromine in the presence of sunlight gives mainly

  • Option 1)

    1 - bromo­-2- methylbutane

  • Option 2)

    2 - bromo­-2- methylbutane

  • Option 3)

    2 - bromo­-3- methylbutane

  • Option 4)

    1 - bromo­-3- methylbutane

 

Answers (2)

best_answer

As we learnt

Chemical Reaction Halogenation of alkane -

When alkane react with halogen in presence of UV light it give free radical substitution reaction.

- wherein

 

 Bromine gets substituted to hydrogen where carbon has least number of hydrogen atoms.

Reactivity order of abstraction of H towards bromination of alkane is 3^{\circ}H> 2^{\circ}H> 1^{\circ}H

 

 


Option 1)

1 - bromo­-2- methylbutane

This option is incorrect.

Option 2)

2 - bromo­-2- methylbutane

This option is correct

Option 3)

2 - bromo­-3- methylbutane

This option is incorrect.

Option 4)

1 - bromo­-3- methylbutane

This option is incorrect.

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