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  • Try this! 500 ml of a hydrocarbon gas burnt in excess of Oxygen yields 2500 ml of CO2 and 3 of literswater vapours. All volume being measured at the same temperature and pressure. The formula of the Hydrocarbon is

500 ml of a hydrocarbon gas burnt in excess of Oxygen yields 2500 ml of CO2 and 3 of liters water vapours. All volume being measured at the same temperature and pressure. The formula of the Hydrocarbon is  

  • Option 1)

    C5H10

  • Option 2)

    C5H12

  • Option 3)

    C4H10

  • Option 4)

    C4H8

 

Answers (1)

best_answer

As we learnt in 

Avogadro’s Law -

Volume - mole relationship

- wherein

\frac{V_{1}}{n_{1}}= \frac{V_{2}}{n_{2}}

 

C_{x}H_{y}+O_{2}\rightarrow CO_{2}+H_{2}O

x\times n_{Cx}H_{y}= n_{CO_{2}}\: \: \: \left ( POAC\: on C \right )

x\times 500= 2500\: \: \: \: \: \: \left ( x= 5 \right )

y\times n\: {C_{x}}H_{y}=2\times n_{H_{2}O}\: \: \: \left ( POAC\: on H\right )

y\times 500= 2\times 3000\: \: \: \: \: y=12

formula = C_{5}H_{12}

 


Option 1)

C5H10

Incorrect

Option 2)

C5H12

Correct

Option 3)

C4H10

Incorrect

Option 4)

C4H8

Incorrect

Posted by

divya.saini

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