A and B toss a fair coin 50 times each simultaenously. what is the probolity that both of them will not get tails at the same toss?

  • Option 1)

    \left ( \frac{1}{4} \right )^{50}

  • Option 2)

    \left ( \frac{2}{3} \right )^{50}

  • Option 3)

    \left ( \frac{1}{2} \right )^{50}

  • Option 4)

    \left ( \frac{3}{4} \right )^{50}

 

Answers (1)

 

Binomial Theorem on Probability -

Then

\dpi{100} P\left ( X= r \right )     or   P(r)

=\ ^{n}C_{\Upsilon }\cdot P^{r }\cdot q^{n-r}

-

 

H H

 

H T

T H

T T

So, both tails  \frac{3}{4} (at least one head)

\therefore \left ( \frac{3}{4} \right )^{50}

because 50 times thrown

 


Option 1)

\left ( \frac{1}{4} \right )^{50}

This solution is incorrect

Option 2)

\left ( \frac{2}{3} \right )^{50}

This solution is incorrect

Option 3)

\left ( \frac{1}{2} \right )^{50}

This solution is incorrect

Option 4)

\left ( \frac{3}{4} \right )^{50}

This solution is incorrect

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