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  • Try this! A point charge q0is place at centre of uniformly charged ring of charge Q, radius R. If Point charge is slight displaced with small force along the ring (Axis) then find out speed of the particle

A point charge q0 is place at centre of uniformly charged ring of charge Q, radius R. If Point charge is slight displaced with small force along the ring (Axis) then find out speed of the particle

  • Option 1)

    v = \sqrt{\frac{2kQ}{R}}

  • Option 2)

    0

  • Option 3)

    v = \sqrt{\frac{2kq_{0}Q}{mR}}

  • Option 4)

    \infty

 

Answers (1)

best_answer

As we have learnt,

 

At centre x = 0 -

E_{c}=0    ,  V_{c}=\frac{kQ}{R}

-

 

 W_{ext} = \Delta K = W_{ext} = \frac{1}{2}mv^2 - 0

W = q\cdot V = q\times \frac{kQ}{R} \Rightarrow \frac{krQ}{R} = \frac{1}{2}mv^2

\Rightarrow v = \sqrt{\frac{2kqQ}{mR}}

 

 


Option 1)

v = \sqrt{\frac{2kQ}{R}}

Option 2)

0

Option 3)

v = \sqrt{\frac{2kq_{0}Q}{mR}}

Option 4)

\infty

Posted by

Plabita

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