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Try this! - Hydrocarbons - JEE Main-2

The major product of the following reaction is :

CH_{3}C\equiv CH\xrightarrow[(ii)\; DI]{(i)\; DCl\left ( 1\; equiv. \right )}

  • Option 1)

     CH_{3}CD(I)CHD(Cl)                

  • Option 2)

    CH_{3}CD(Cl)CHD(I)

  • Option 3)

    CH_{3}CD_{2}CH(Cl)(I)

  • Option 4)

    CH_{3}C(I)(Cl)CHD_{_{2}}

Answers (1)
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V Vakul

 

Markovnikov's Rule -

Negative part of the reagent attacks on that carbon of multiple bond which have less number of   hydrogen atoms.

- wherein

 

 

Addition of Hydrogen halide on alkyne -

Reaction takes place according to Markovnikov's rule.

- wherein

 

 

CH_{3}C\equiv CH\xrightarrow[(ii)\; DI]{(i)\; DCI\left ( 1\; equiv. \right ))}

                     Markonikov rule

CH_{3}C\equiv CH\xrightarrow{(i)DCl}

                                              


Option 1)

 CH_{3}CD(I)CHD(Cl)                

Option 2)

CH_{3}CD(Cl)CHD(I)

Option 3)

CH_{3}CD_{2}CH(Cl)(I)

Option 4)

CH_{3}C(I)(Cl)CHD_{_{2}}

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