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If a simple pendulum oscillates with an amplitude of 50 mm and time period of 2s, then its maximum velocity is

  • Option 1)

    0.10 m/s

  • Option 2)

    0.16 m/s

  • Option 3)

    0.25 m/s

  • Option 4)

    0.50 m/s

 

Answers (1)

best_answer

As discussed in

Relation of velocity and displacement -

v= w\sqrt{A^{2}-x^{2}}
 

- wherein

\rightarrow  x is displacement from mean position

\rightarrow  A is Amplitude.

 

 V=A\omega =A \frac{2\pi }{T} = 50\times 10^{-3}\times \frac{2\pi }{2}

 

V=50\times 10^{-3}\times 3.14=0.16 m/s


Option 1)

0.10 m/s

This solution is incorrect.

Option 2)

0.16 m/s

This solution is correct.

Option 3)

0.25 m/s

This solution is incorrect.

Option 4)

0.50 m/s

This solution is incorrect.

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Plabita

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