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  • Try this! If edge length of unit cell of diamond is 698 pm then the radius of Carbon atom is

If edge length of unit cell of diamond is 698 pm then the radius of Carbon atom is

  • Option 1)

    170 pm

  • Option 2)

    154 pm

  • Option 3)

    151 pm

  • Option 4)

    160 pm

 

Answers (1)

best_answer

radius of cation atom = \frac{a\sqrt{3}}{8}

                                 =\frac{698\times 1.732}{8}=151.12pm

 

Diamond structure -

In the structure of diamond C atom present at all corners , all face centres and 50 % tetrahedral voids.

Bond length i.e distance between 2 nearest C atom = \frac{\sqrt{3}a}{4}

Radius of C atom =  rc

rc = \frac{\sqrt{3}a}{8}

Packing efficiency of diamond is 34%

- wherein

Number of C atom per unit cell = 8

a = edge length of unit cell

 

 


Option 1)

170 pm

This is incorrect

Option 2)

154 pm

This is incorrect

Option 3)

151 pm

This is correct

Option 4)

160 pm

This is incorrect

Posted by

prateek

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