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If $\alpha$ is the degree of dissociation of $Na_{2}SO_{4}$ the vant Hoff’s factor (i) used for calculating the molecular mass is

Option 1)
$1+\alpha$

Option 2)
$1-\alpha$

Option 3)
$1+2\alpha$

Option 4)
$1-2\alpha$

Answers (1)

best_answer

As we learnt in

Vant Hoff factor for dissociation -

$i= 1+(n-1)\alpha$

Where

$n$ is the no. of dissociated particles

$\alpha =$ degree of association

- wherein

$NaC l \: \: \: n = 2$

$CaCl_{2} \: \: \: n = 3$

$K_{4}[F(CN_{6})]\: \: \: \: \: n=5$

$Na_{2}SO_{4}\rightleftharpoons 2Na^{+}+SO{_{4}}^{2-}$

$1-\alpha$ $2\alpha$ $\alpha$

$i=1-\alpha+2\alpha+\alpha$

$i=1+2\alpha$

Correct option is 3.

Option 1)

$1+\alpha$

This is an incorrect option.

Option 2)

$1-\alpha$

This is an incorrect option.

Option 3)

$1+2\alpha$

This is the correct option.

Option 4)

$1-2\alpha$

This is an incorrect option.

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