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Try this! The number of ways in which 12 balls can be divided between two friends, one receiving 8 and the other 4, is:

The number of ways in which 12 balls can be divided between two friends, one receiving 8 and the other 4, is:

  • Option 1)

    \frac{12!}{8!4!}

  • Option 2)

    \frac{12!2!}{8!4!}

  • Option 3)

    \frac{12!}{8!4!2!}

  • Option 4)

    None of these

 
Answers (1)
137 Views

As learnt in concept

Rule for Division into Groups -

The number of ways in which (m + n) different things can be divided into two groups which contain m and n things respectively is \frac{(m+n)!}{m!\ n!}.

-

 

 grouping ways are \frac{12!}{8!4!}
now they can be done in any way

So,

\frac{12!}{8!4!}\times 2!


Option 1)

\frac{12!}{8!4!}

This is incorrect option

Option 2)

\frac{12!2!}{8!4!}

This is correct option

Option 3)

\frac{12!}{8!4!2!}

This is incorrect option

Option 4)

None of these

This is incorrect option

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