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  • Two beams of light having intensities I and 4 I interfere to produce a fringe pattern on a screen. The phase difference between the two beams are <img alt="\mathrm{\pi / 2}" src="https://entranceco

Two beams of light having intensities I and 4 I interfere to produce a fringe pattern on a screen. The phase difference between the two beams are \mathrm{\pi / 2} and \mathrm{ \pi / 3} at points \mathrm{ \mathrm{A}} and \mathrm{ \mathrm{B}} respectively. The difference between the resultant intensities at the two points is \mathrm{ x I.} The value of \mathrm{ x} will be _________.

Option: 1

2


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\mathrm{I_1=I }

\mathrm{I_2=4 I }

\mathrm{I_{\text {resultant }}=I_1+I_2+2 \sqrt{I_1 I_2} \cos \phi }

\mathrm{I_A=I+4 I+4 I \cos (\pi / 2) }

\mathrm{I_A=5 I }

\mathrm{I_B=I+4 I+4 I \cos (\pi / 3) }

\mathrm{I_B=7 I}
The difference between two intensities at a point is,

\mathrm{I_{B}-I_{A}=2I}

\mathrm{x=2}

Posted by

seema garhwal

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