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Two bodies are projected from ground with same speeds 40 \mathrm{~ms}^{-1} at two different angles with respect to horizontal. The bodies were found to have same range. If one of the body was projected at an angle of 60^{\circ},with horizontal then sum of the maximum heights, attained by the two projectiles, is __________ m.
(Given \mathrm{g}=10 \mathrm{~ms}^{-2} )

Option: 1

80


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

In Range is same.

\alpha+\beta=90^{\circ}
\alpha=60^{\circ}
\beta=30^{\circ}
\mathrm{H}_{1}+\mathrm{H}_{2}=\frac{\mathrm{u}_{1}^{2} \sin ^{2} 60^{\circ}}{2 \mathrm{~g}}+\frac{\mathrm{u}_{2}^{2} \sin ^{2} 30^{\circ}}{2 \mathrm{~g}}
                 =\frac{\mathrm{u}^{2}}{2 \mathrm{~g}}\left(\frac{3}{4}+\frac{1}{4}\right) \quad\left[\mathrm{u}_{1}=\mathrm{u}_{2}\right]
\mathrm{H}_{1}+\mathrm{H}_{2}=\frac{(40)^{2}}{20}=80 \mathrm{~m}

Posted by

Ritika Jonwal

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