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Two electrons (each of charge →e and mass →m ) are attached at each end of a light rigid rod of length 2r. The rod is rotated at constant angular speed about a perpendicular axis passing through its centre. The ratio of angular momentum about the axis of rotation to the magnetic dipole moment of the system is:

Option: 1

\frac{2 \mathrm{me}}{3}


Option: 2

\mathrm{\frac{e^2}{2 m}}


Option: 3

\frac{5 \mathrm{~m}}{2 \mathrm{e}}


Option: 4

\mathrm{\frac{2 m}{e}}


Answers (1)

best_answer

\mathrm{ \mathrm{L}=\mathrm{l} \omega=2 \mathrm{m} r^2 \omega \\ }

\mathrm{ \mathrm{M}=\mathrm{iA}=\left(\frac{2 \mathrm{e}}{\mathrm{T}}\right) \pi \mathrm{r}^2 }

      \mathrm{ =\left(\frac{2 \mathrm{e}}{2 \pi / \omega}\right) \pi \mathrm{r}^2 }

      \mathrm{ =e \omega r^2 }

\mathrm{ \therefore \quad \frac{\mathrm{L}}{\mathrm{M}}=\frac{2 \mathrm{~m}}{\mathrm{e}} }

Posted by

Gautam harsolia

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