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Two elements \mathrm{A}$ and $\mathrm{B} which form 0.15 moles of \mathrm{A}_{2} \mathrm{~B}$ and $\mathrm{AB}_{3}  type compounds. If both \mathrm{A_{2} {B}~ and~ A B_{3}}  weigh equally, then the atomic weight of A is____________ times of atomic weight of B.

Option: 1

2


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

Given in Q:

\text { Molar mass of } \mathrm{A_{2} B}=\text { Molar mass of } \mathrm{A B_{3}}

\mathrm{2 A+B=A+3 B}

A=Atomic weight of A
B= Atomic weight of B

\text{A = 2B}

Thus, atomic weight of A is 2 times of atomic weight of B

Hence, answer is 2.

Posted by

Ritika Kankaria

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