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  • Two first order reactions have haff-lives in the ratio .Calculate the ratio of time intervals <img alt="\math

Two first order reactions have haff-lives in the ratio 16: 1.Calculate the ratio of time intervals \mathrm{t_{1}: t_{2}}. The time \mathrm{t_{1}} is for \mathrm{\left(\frac{1}{4}\right)^{\text {th }}}completion of first reaction and the time \mathrm{t_{2}} is for \mathrm{\left(\frac{3}{4}\right)^{\text {th }}} completion of second reaction.

Option: 1

3.32 :1


Option: 2

1:0.5


Option: 3

4:1.5


Option: 4

6.64:1


Answers (1)

best_answer

\mathrm{t_{1}=\frac{\left(t_{1 / 2}\right)_{1}}{0.693} \ln \left(\frac{1}{1-\frac{1}{4}}\right)}
\mathrm{t_{2}=\frac{\left(t_{1 / 2}\right)_{2}}{0.693} \ln \left(\frac{1}{1-\frac{3}{4}}\right)}

\mathrm{\frac{t_{1}}{t_{2}}=\frac{16}{1} \frac{\ln (4 / 3)}{\ln (4)}=\frac{3.32}{1}}

Posted by

Suraj Bhandari

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