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Two infinitely long linear conductors are arranged perpendicular to each other and are in mutually perpendicular planes as shown in figure. If I1 = 2A along the y-axis and I2 = 3A along negative z-axis and AP = AB = 1 cm. The value of magnetic field strength \overrightarrow{B}  at P is 

Option: 1

(3\times 10^{-5}T)\widehat{j}+\left ( -4\times 10^{-5} T\right )\widehat{k}


Option: 2

(3\times 10^{-5}T)\widehat{j}+\left (4\times 10^{-5} T\right )\widehat{k}


Option: 3

(4\times 10^{-5}T)\widehat{j}+\left ( 3\times 10^{-5} T\right )\widehat{k}


Option: 4

(-3\times 10^{-5}T)\widehat{j}+\left ( 4\times 10^{-5} T\right )\widehat{k}


Answers (1)

best_answer

 

Magnetic Field Due to a Straight Wire -

B=\frac{\mu_{o}i}{4\pi r}(\sin\phi_{1}+\sin\phi_{2})

- wherein

 

 

For Infinite Length -

\phi_{1}=\phi_{2}=90^{\circ}

B=\frac{\mu_{o}}{4\pi}\:\frac{2i}{r}\:

- wherein

 

 

Magnetic field strength at P due to I1

\overrightarrow{B}_{1} = \frac{\mu _{0}I_{1}}{2\pi (AP)}\widehat{k} = \frac{4\pi \times 10^{-7}\times 2}{2\pi \times 1\times 10^{-2}}\widehat{k} = (4\times 10^{-5}T)\widehat{k}

Magnetic field strength at P due to I2

\overrightarrow{B}_{2} = \frac{\mu _{0}I_{2}}{2\pi (BP)}\widehat{j} = \frac{4\pi \times 10^{-7}\times 3}{2\pi \times 2\times 10^{-2}}\widehat{j} = (3\times 10^{-5}T)\widehat{j}

Hence , \overrightarrow{B}= (3\times 10^{-5}T)\widehat{j}+ (4\times 10^{-5}T)\widehat{k}

Posted by

shivangi.shekhar

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