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Two light beams of intensities \mathrm{4I} and \mathrm{9I} interfere on a screen. The phase difference between these beams on the screen at point \mathrm{A} is zero and at point \mathrm{B}$ is $\pi. The difference of resultant intensities, at the point \mathrm{A \: and \: B}, will be ___________ \mathrm{I.}

Option: 1

24


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\mathrm{I_{\text {resultant }}=I_1+I_2+2 \sqrt{I_1} \sqrt{I_2} \cos \phi}

At point \mathrm{A,}

\mathrm{I_A=4 I+9 I+2 \sqrt{4 I} \sqrt{9 I} \cos 0^{\circ}}

\mathrm{I_A=25 \mathrm{I}}

At point \mathrm{B}

\mathrm{I_B=4 I+9 I+2 \sqrt{4 I} \sqrt{9 I} \cos \pi}

\mathrm{I_B=I}

The difference of resultant intensities at \mathrm{A\: \& \: B \, is\: \: I_A-I_B=24 I}

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Pankaj

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