Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Two light waves of wavelengths 800 and are used in Young's double slit experiment

Two light waves of wavelengths 800 and 600 \mathrm{~nm} are used in Young's double slit experiment to obtain interference fringes on a screen placed 7 \mathrm{~m} way from plane of slits. If the two slits are separated by 0.35 \mathrm{~mm},  then shortest distance from the central bright maximum to the point where the bright fringes of the two wavelength coincide will be ______\mathrm{mm}.

Option: 1

48


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\mathrm{d}=0.35 \mathrm{~mm}, \mathrm{D}=7 \mathrm{~m}
To Coincide, \mathrm{\quad n_{1}\left(\frac{\lambda_{1} D}{d}\right)=n_{2}\left(\frac{\lambda_{2} D}{d}\right)}
                       \frac{\mathrm{n}_{1}}{\mathrm{n}_{2}}=\frac{\lambda_{2}}{\lambda_{1}}=\frac{6}{8}=\frac{3}{4}

3^{\text {rd }}$ Maxima of $\lambda_{1}$ and $4^{\text {th }}$ Maxima of $\lambda_{2} 

\mathrm{Y}=\frac{3 \lambda_{1} \mathrm{D}}{\mathrm{d}}=\frac{3 \times 800 \times 10^{-9} \times 7}{35 \times 10^{-5}}
\mathrm{Y}=3 \times 160 \times 10^{-4} \mathrm{~m}
\mathrm{Y}=48 \mathrm{~mm}

Posted by

Shailly goel

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2025 Session 2 City Slip (OUT) Live: NTA exam city intimation slip link available; admit card date
anam-khan

AESL expands Aakash Digital 2.0 to offer AI-powered coaching for NEET, JEE, Olympiads
anam-khan

Bihar Board extends BSEB Super 50 free coaching application last date to March 26

Latest Question