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Two transparent media having refractive indices 1.0 and 1.5 are separated by a spherical refracting surface of radius of curvature 30 \mathrm{~cm}.The centre of curvature of surface is towards denser medium and a point object is placed on the principle axis in rarer medium at a distance of 15 \mathrm{~cm} from the pole of the surface. The distance of image from the pole of the surface is_______ \mathrm{cm}.

Option: 1

30


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)



\frac{1.5}{\mathrm{v}}-\frac{1}{(-15)}=\frac{1.5-1}{30}

\Rightarrow \frac{1.5}{\mathrm{v}}-\frac{1}{60}-\frac{1}{15}=\frac{1-4}{60}

\mathrm{~V}=-30 \mathrm{~cm}

=30 \mathrm{~cm}

Posted by

Kshitij

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