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Two wires each of radius 0.2 cm and negligible mass, one made of steel and the other made of brass are loaded as shown in the figure. The elongation of the steel wire is _______ × 10^{-6} \mathrm{~m}. [Young's modulus for steel =  2 \times 10^{11} \mathrm{Nm}^{-2} \text { and } \mathrm{g}=10 \mathrm{~ms}^{-2}   
                                                        

Option: 1

20


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer


\begin{aligned} & \mathrm{T}_2=\mathrm{T}_1+20=20+11.4 \\ & \mathrm{~T}_2=31.4 \\ & \therefore \text { Elongation in steel wire } \\ & \Delta \mathrm{L}=\frac{\mathrm{T}_2 \mathrm{~L}}{\mathrm{AY}} \\ & =\frac{31.4 \times 1.6}{\pi\left(0.2 \times 10^{-2}\right)^2 \times 2 \times 10^{11}} \\ & =2 \times 10^{-5} \\ & \Delta \mathrm{L}=20 \times 10^{-6} \mathrm{~m} \end{aligned}

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Nehul

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