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 Under the same load, wire A having length 5.0 \mathrm{~m} and cross section 2.5 \times 10^{-5} \mathrm{~m}^{2} stretches uniformly by the same amount as another wire B of length 6.0 \mathrm{~m} and a cross section of 3.0 \times 10^{-5} \mathrm{~m}^{2} stretches. The ratio of the Young's modulus of wire A to that of wire B will be :  

Option: 1

1: 1


Option: 2

1: 10


Option: 3

1: 2


Option: 4

1: 4


Answers (1)

best_answer

By Hooke's Law,

\mathrm{Y}=\frac{\mathrm{FL}}{\mathrm{A} \Delta \mathrm{L}}

F, \Delta \mathrm{L} \rightarrow Same

\mathrm{\frac{Y_{1} A_{1}}{L_{1}}=\frac{Y_{2} A_{2}}{L_{2}}}
\mathrm{\frac{Y_{1}}{Y_{2}}=\frac{3 \times 10^{-5}}{2.5 \times 10^{-5}} \times \frac{5}{6}=\frac{1}{1}}

Posted by

vishal kumar

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