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What is Gravitational potential due to uniform circular ring at a point on its Axis ??

Answers (1)

A avinash.dongre

As shown in the below figure

Gravitational potential due to uniform circular ring at a point on its axis is given by

$V=-\frac{GM}{\sqrt{a^{2}+r^{2}}}$

Where

$r=$ the distance from the ring

$a\rightarrow$ radius of Ring

$V\rightarrow$ Potential

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