What is Gravitational potential due to uniform circular ring at a point on its Axis ??

Answers (1)

As shown in the below figure

 Gravitational potential due to uniform circular ring at a point on its axis is given by

V=-\frac{GM}{\sqrt{a^{2}+r^{2}}}

Where

r= the distance from the ring

a\rightarrow radius of Ring

V\rightarrow Potential 

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