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What is the equation of director circle of the circle x^2+y^2+2x-4y+1=0

Option: 1

x^2+y^2+2x-4y+2=0


Option: 2

x^2+y^2+2x-4y+3=0


Option: 3

x^2+y^2+2x-4y-2=0


Option: 4

x^2+y^2+2x-4y-3=0


Answers (1)

best_answer

\\x^2+y^2+2x-4y+1=0 \\Centre:(-1,2), \,\,Radius = 2 \\ \text{As we know, director circle has same centre and } \\\sqrt{2} \text{ times the radius of original circle } \\ \text{Hence, the equation of director circle is}\\ (x+1)^2+(y-2)^2=(2\sqrt{2})^2\\ x^2+y^2+2x-4y-3=0

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Pankaj Sanodiya

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