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  • What is the least distance of (4,3) from <div class='qna-optio

What is the least distance of (4,3) from x^2 + y^2 = 9 ?

Option: 1

4 


Option: 2

3 


Option: 3

2 


Option: 4

1 


Answers (1)

best_answer

The circle is x2 + y2 - 9 = 0

A is the point and circle has centre C and radius r.

Checking position of point with respect to circle

S1 = 16 + 9 - 9 = 16 > 0

So A lies outside the circle

 

So, Least distance = AC - r 

               \\= \sqrt {4^2 + 3^2 } - 3 \\= 5 -3 = 2

Posted by

Rishabh

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