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  • What is the locus of point equidistant from the point (3,0) and (5,2) ?  Option: 1 x - y = 5 <div class='qna-option

What is the locus of point equidistant from the point (3,0) and (5,2) ?  

Option: 1

x - y = 5 


Option: 2

x + y = 5 


Option: 3

x + 2y = 3 


Option: 4

x - y = 2 


Answers (1)

best_answer

Let P(h,k) be the required point

Given PA = PB

So, PA2 = PB2
\\(h-3)^2+k^2=(h-5)^2+(k-2)^2\\ h^2-6h+9+k^2=h^2-10h+25+k^2-4k+4\\4h+4k-20=0\\h+k-5=0\\ x+y-5=0

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