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What is the momentum of a photon of frequency 2\times10^{15}Hz?

Option: 1

4.41\times 10^{-27}kg \: m/s


Option: 2

6.63\times 10^{-34}kg \: m/s


Option: 3

6.63\times 10^{-25}kg \: m/s


Option: 4

4.14\times 10^{-15}kg \: m/s


Answers (1)

best_answer

Light propagates in bundles of energy called photons. The energy of one quantum is given by the equation E= hv, where h is Planck's constant, v is the frequency of light, and c is the speed of light. The syllabus also covers the properties of photons, including their energy, momentum, mass, and behavior during collisions with other particles. It is important to note that photons are electrically neutral and do not carry any electric charge. The momentum of a photon can be calculated using the equation p= h/\lambda or p= E/c, where h is Planck's constant, \lambda  is the wavelength of light, E is the energy of the photon, and c is the speed of light.

p= hv/c
=\left(6.626 \times 10^{-34} J . s \times 2 \times 10^{15} Hz\right) /\left(3\times 10^{8} \mathrm{~m}/s\right)
=4.41\times 10^{-27} kg\, m/s
Therefore, the momentum of a photon of frequency =2\times 10^{15}Hz is =4.41\times 10^{-27} kg\, m/s

Posted by

Ajit Kumar Dubey

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