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  • What will the photon flux of a radioactive metal if the number of photons emmiting  per second are <img alt="6 \times 10^6" src="https://entrancecorner.oncodecogs.com/gif.latex?6%20%5Ctim

What will the photon flux of a radioactive metal if the number of photons emmiting  per second are 6 \times 10^6 through a surface area of 2 m^2 ?

Option: 1

6\times 10^6 \ \text{sec}^{-1} \ m^{-2}


Option: 2

3\times 10^6 \ \text{sec}^{-1} \ m^{-2}


Option: 3

1.2 \times 10^7 \ \text{sec}^{-1} \ m^{-2}


Option: 4

3\times 10^7 \ \text{sec}^{-1} \ m^{-2}


Answers (1)

best_answer

 

 

Photon Flux -

The photon flux is defined as the number of photons per second per unit
area:
\phi=\frac{\text { No of photons per sec }}{\ Area }

\phi=\frac{6\times 10^6}{ 2 m^{2}\sec}

3\times 10^6 \ \text{sec}^{-1} \ m^{-2}

 hence the correct option will be 2. 

Posted by

Kuldeep Maurya

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