Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • When an electron in hydrogen atom is excited, from its 4th to 5th stationary orbit, the change in angular momentum of electron is (Planck’s constant: <img alt="h=6.6 \ti

When an electron in hydrogen atom is excited, from its 4th to 5th stationary orbit, the change in angular momentum of electron is (Planck’s constant: h=6.6 \times 10^{-34} \mathrm{~J}-\mathrm{s})

Option: 1

4.16 \times 10^{-34} \mathrm{~J}-\mathrm{s}


Option: 2

3.32 \times 10^{-34} \mathrm{~J}-\mathrm{s}


Option: 3

1.05 \times 10^{-34} \mathrm{~J}-\mathrm{s}


Option: 4

2.08 \times 10^{-34} \mathrm{~J}-\mathrm{s}


Answers (1)

best_answer

Change in the angular momentum

\mathrm{\Delta L=L_2-L_1=\frac{n_2 h}{2 \pi}-\frac{n_1 h}{2 \pi} \Rightarrow \Delta L=\frac{h}{2 \pi}\left(n_2-n_1\right)}
        \mathrm{=\frac{6.6 \times 10^{-34}}{2 \times 3.14}(5-4)=1.05 \times 10^{-34} J-S}

Posted by

seema garhwal

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

BTech Admission 2025 Live: JEE Mains, SRMJEEE, MET registrations underway; MHT CET syllabus updates
anam-khan

Centre issues coaching guidelines, prohibits centres from using false claims like '100% selection'
anam-khan

BTech Admissions 2025 Live: JEE Mains, SRMJEE, VITEEE dates out; AEEE, MET registrations underway

Latest Question