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\mathrm{ZnCl_2} when dissolved in \mathrm{NaOH} gives a white precipitate X which dissolves to give a solution of Y. What is X and Y?

Option: 1

\mathrm{ZnO, Zn(OH)_2}


Option: 2

\mathrm{Zn(OH)_2, Na_2ZnO_2}


Option: 3

\mathrm{Zn(OH)_2, NaZnO}


Option: 4

\mathrm{ZnO, NaZnO}


Answers (1)

best_answer

On addition of sodium hydroxide solution, it gives a white precipitate of zinc hydroxide, which is soluble in excess of \mathrm{NaOH} solution on heating due to the formation of sodium zincate.

\mathrm{ZnCl_2 + 2NaOH \rightarrow Zn(OH)_2 + 2NaCl}

\mathrm{Zn(OH)_2 + 2NaOH \rightarrow Na_2ZnO_2 + 2H_2O}

Hence option 2 is correct.

 

Posted by

Ritika Harsh

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